Question

If a=34, b=33,=c=33 ,then a3 + b3 + c3 - 3abc = ??

Answer 1

given that a = 34. b= 33 c= 33
So,
(34)cube + (33) cube + (33) cube - 3(34)(33)(33)
39304+35937+35937 - 111078
= 111178 - 111078
= 100
hope this will help you.

Answer 2

Answer:

100

Step-by-step explanation:

a=34, b=33, c=33

Because, a³ +b³ +c³ - 3abc = (a+b+c) × 12 [(a−b)² +(b−c)² + (c−a)² ]

= (34+33+33) × 12

[(34−33)² +(33−33)² +(33=34)² ]

= 100×12 (1+0+1)

= 100×1

= 100

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