Question

if A=35 ,B=15and C =40 then the value of tanA.tsnB+ tanB.tanC+ tanC.tanA​

Answer 1

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GIVEN :-

A = 35°, B = 15°, C = 40°

TO FIND :-

tan A.tan B+tan B. tan C+tanC.tan A

SOLUTION :-

taking

tan(( A + B ) + C ) = 35°+15°+40°

tan(( A + B ) + C) = tan90°

tan( A + B ) + tanC/1−tan( A + B )tanC = 1/0

1 - tan( A + B )tan C = 0

1 - tan( A + B )tan C = 1

(1/tanA + tanB / 1 - tanA tan B)tan C = 1

tanA tanC + tanB tanC = 1 - tanA tanB

tanA tanB + tanB tanC + tanC tanA = 1