If a= -37
d = 4
Find sum in AP up to 12 terms
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We know d=6 and sum of 12 terms is 468
S12 = 12/2 [2a+(12−1)(6)]
⇒468=6[2a+66]
⇒468=12a+396
⇒a=6
So, the 10th term is a+(n−1)d=6+9×6=60
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