Question

If A = (3a 2 -4b-1), B = (6a 2 +3b-8) and C = ( 4a 2 -9b+3), then find the
value of A-B+C.
please help

Answer 1

Answer:

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Step-by-step explanation:

Answer 2

Answer:

A-B+C

(3a 2 -4b-1)-(6a 2 +3b-8) +4a 2 -9b+3)

=3a 2 -4b-1-6a 2 -3b+8+4a 2 -9b+3

=(3+4-6) a 2+(-4-3-9) b+(-1+8+3)

=a 2+(-16) b+10

=a 2-16b+10

This is the answer.

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