If A=(3a2-46-1)
B=(62²-36-8)
C - (4a2 - 9b+3) find A-B+C
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how much 2x3-3x2+4x+5 greater than 2×3+7×2-2×+7
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Answer:
A-B+C
(3a 2 -4b-1)-(6a 2 +3b-8) +4a 2 -9b+3)
=3a 2 -4b-1-6a 2 -3b+8+4a 2 -9b+3
=(3+4-6) a 2+(-4-3-9) b+(-1+8+3)
=a 2+(-16) b+10
=a 2-16b+10
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