if (a + 3b) = 6 show that a^3+ 27b^3+ 54 ab = 216
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(a +3b) = 6
Cubing both sides we get.
(a +3b)³ = 6³
or, a³ + (3b)³ + 3.a.3b(a+3b) = 216
or, a³ + 27b³ + 9ab. 6 =216
or, a³ +27b³ + 54ab = 216_(proved)__
Proud to help u.
Cubing both sides we get.
(a +3b)³ = 6³
or, a³ + (3b)³ + 3.a.3b(a+3b) = 216
or, a³ + 27b³ + 9ab. 6 =216
or, a³ +27b³ + 54ab = 216_(proved)__
Proud to help u.
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