Question

If (a+3b)=6 sow that (a^3+8b^3+27c^3)=18abc
please solve this problem
please i want now itself please..tomorrow I have exam..(I dont want any useless answers)​

Answer 1

hi

friend...

Step-by-step explanation:

a+2b+3c=0 then

a+2b=-3c

(a+2b)3=(-3c)3 (By cubing)

a3+(2b)3+3(a)(2b)(a+2b) = -27c3

a3+8b3+6ab (-3c) = -27c3 [a+2b=-3c]

a3+8b3-18abc = -27c3

a3+8b3+27c3 = 18abc