Question

If à = 3i– 2j+ 4k B = 3i – 2j + 4k C = i + 2j + 2k then find the value of
Ảx (B x C)​

Answer 1

Explanation:

A×(B×C)

1) B×C

B:- 3i - 2j + 4k

C:- i + 2j + 2k

By applying determinant method

B×C= (-4-8)i-(6-4)j+(6+2)k

= -12i - 2j + 8k

2) Ax(B×C)

A:- 3i - 2j + 4k

(B×C):- -12i - 2j + 8k

= (-16+8)i-(24+48)j+(-6-24)k

=》-8i - 72j - 30k