Question

If a = 3i +4j and = 7i +24j, find the vector having the same magnitude as b and parallel to ā.​

Answer 1

Answer:

$|B| = \sqrt{ {7}^{2} + (24) {}^{2} } = \sqrt{625} = 25$

Unit vector in the direction of A will be A

$= \frac{3i + 4j}{5}$

So required vector

$= 25( \frac{3i + 4j}{5} ) = 15i + 20j$

Answer 2

refer to the attachment