Question

if a=3i+4j and b=3j+4k then b along a is​

Answer 1

Answer:

$\frac{12}{5}$

Explanation:

B along A vector

$|a| |b| \cos = a.b \\ ab \cos = (3i + 4j).(3j + 4k) \\ b \cos = \frac{3 \times 0 + 4 \times 3 + 4 \times 0}{ \sqrt{ {3}^{2} + {4}^{2} } } \\ b \: along \: a = \frac{12}{5}$