If a=3i+6j-2I then the unit vector parallel to a is?
Answers
Answered by
13
Answer:
(3i + 6j - 2k)/7
Explanation:
We know,
Unit vector = vector/magnitude
In the given question,
Vector = 3i + 6j - 2k
Magnitude = √(3² + 6² + (-2)²)
Magnitude = √(9 + 36 + 4) = √49
Magnitude = 7
Therefore,
Unit vector = (3i + 6j - 2k)/7
Answered by
4
Unit vector = (3i + 6j - 2k)/7
for more Explanation , Refer the given attachment
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