Physics, asked by azzzz7983, 1 month ago

If a=3i+6j-2I then the unit vector parallel to a is?

Answers

Answered by abhi569
13

Answer:

(3i + 6j - 2k)/7

Explanation:

We know,

Unit vector = vector/magnitude

In the given question,

Vector = 3i + 6j - 2k

Magnitude = √(3² + 6² + (-2)²)

Magnitude = √(9 + 36 + 4) = √49

Magnitude = 7

Therefore,

Unit vector = (3i + 6j - 2k)/7

Answered by jaswasri2006
4

Unit vector = (3i + 6j - 2k)/7

for more Explanation , Refer the given attachment

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