Question

If A= 3i - j - 4k, B = - 2i + 4j - 3k, C =i + 2j - k, find | 3A -2B +4C |

Answer 1

Answer:

2A+7B+4C=0

2(3i+5j-2k)+7(-3j+6k)=-4C

6i+10j-4k-21j+42k=4C

6i-11j+38k=4C

c=2i-11\4j+19\2k.

Hope You Will Like My ANs Mate......

Answer 2

Answer:

If A= 3i - j - 4k, B = - 2i + 4j - 3k, C =i + 2j - k,  | 3A -2B +4C |=$19.94$

Step-by-step explanation:

A vector is a physical quantity that has both magnitude and direction

From the question, we have three vectors

$A=3i-j-4k\\B=-2i+4j-3k\\C=i+2j-k$

In general, we can represent a  vector as $A=ai+bj+ck$

to multiply a vector by a constant λ, all the components should be multiplied by λ as given below

$\lambda A=\lambda ai+\lambda bj+\lambda ck$

likewise,

$3A=9i-3j-12k\\2B=-4i+8j-6k\\4C=4i+8j-4k$

the required vector is $3A-2B+4C=17i-3j-10k$

now the magnitude of the vector 3A-2B+4C is the root of the sum of squares of components of the given vector

$/3A-2B+4C/=$ $\sqrt{17^{2} +3^{2} +10^{2} } =19.94$