Question

if A=3i-j-4k B=-2i+4j-3k C=i+2j-k find its magnitude

Answer 1

here is ur answer.............

Answer 2

Answer:

If a vector A=3i-j-4k its magnitude is $\sqrt{26}$ for vector B=-2i+4j-3k the magnitude is $\sqrt{29}$ for vector C=i+2j-k the magnitude is $\sqrt{6}$

Explanation:

A vector is a physical quantity that has both magnitude and direction.

In general, a vector is represented as  $A=ai+bj+ck$

where $a,b,c$ are its components and $i,j,k$ are unit vectors along X, Y, Z axes respectively (it give the directions of a vector)

Now the magnitude of a vector is given by the root of the sum of squares of its components, that is

$/A/=\sqrt{a^{2} +b^{2} +c^{2} }$

here the first vector is $A=3i-j-4k$

and its magnitude is $/A/=\sqrt{3^{2} +1^{2} +4^{2} } =\sqrt{26}$

the second vector is $B=-2i+4j-3k$

and its magnitude is $/B/=\sqrt{2^{2} +4^{2} +3^{2} } =\sqrt{29}$

the third vector is $C=i+2j-k$

and its magnitude is $/C/=\sqrt{1^{2} +2^{2} +1^{2} } =\sqrt{6}$