Physics, asked by SiddhiMali, 9 months ago

If A = 3i - j - 4k, B=-2i +4j - 3k, C=i+2j-k. Find the magnitude of A +B+C vector​

Answers

Answered by puneet098
8

Answer:

√26 +√20+√6

Explanation:

magnitude of a= √3²+(-1)²+(-4)²=√26

b=√(-2)²+(4)²+(-3)²=√29

c=√(1)²+2²(-1)²=√6

a+b+c=√26+√29+√6

Answered by handgunmaine
2

The magnitude of A +B+C vector​ is \sqrt{93}.

Explanation:

Vector A, 3i-j-4k

Vector B, -2i+4j-3k

Vector C, i+2j-k

Considering A+B+C as :

A+B+C=3i-j-4k+-2i+4j-3k+i+2j-k\\\\A+B+C=2i+5j-8k

The magnitude of A+B+C is :

|A+B+C|=\sqrt{2^2+5^2+(-8)} \\\\|A+B+C|=\sqrt{93}

So, the magnitude of A +B+C vector​ is \sqrt{93}.

Learn more,

Vectors

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