If A(3x,x-1), B(3x+2,X),C(3x+3,X+2),D (3x + 1, x+l) are vertices of ABCD Show
that ABCD is a parallelogram
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Answer:
Proof is Provided Below
Step-by-step explanation:
Here's a simple method to solve this question:
We know that the opposite sides of the parallelogram are parallel
This implies that the slope of the opposite sides are equal
SO NOW,
In parallelogram ABCD,
TO PROVE: SIDE AB II CD AND SIDE AC II BD
Slope(m) = y2 - y1/x2-x1
slope of AB = x-(x-1)/3x+2-3x
= 1/2
slope of CD = x+1-(x+2)/3x+1-(3x+3)
= -1/-2
= 1/2
Similarly we can prove that slope of AC = slope of BD
Hence proved that ABCD are vertices of a parallelogram.
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