Question

If A =3x2+4x+1,B=5x2−3x+8,C=4x2−7x−3, find the value of B + C –A.

Answer 1

$\bigstar$ Question:

If $\sf A =3x^{2} + 4x+1, \: B=5x^{2} -3x+8, \: C=4x^{2} -7x-3,$ find the value of $\sf B+C-A$

$\bigstar$ Solution:

$\sf B+C-A = (5x^{2} -3x+8)+(4x^{2}-7x-3)-(3x^{2}+4x+1)$

$\sf 5x^{2}-3x+8+4x^{2}-7x-3-3x^{2}+4x+1$

Now, taking the like terms,

$\sf 5x^{2}+4x^{2}-3x^{2}-3x-7x+4x+8-3+1$

$\implies \boxed{\sf 6x^{2}-6x+6}$

∴ The value of $\sf B+C-A$ is $\sf 6x^{2}-6x+6$

Answer 2

Step-by-step explanation:

A=3x^2+4x+1, B=5x^2-3x+8 and C= 4x^2-7x-3

B+C-A=(5x^2-3x+8)+(4x^2-7x-3)-(3x^2+4x+1)

=5x^2+4x^2-3x^2-3x-7x+4x+8-3+1

=6x^2-6x+6

Hope it's helpful.