Question

If A =3x2+4x+1 ,B=5x2−3x+8,C= 4x2−7x−3 , find the value of B + C – A.

Answer 1

Given,

• $\sf{A=3x^2+4x+1$

• $\sf{B=5x^2-3x+8$

• $\sf{C=4x^2-7x-3$

We have to find B + C - A

$\implies\sf{B+C-A=(5x^2-3x+8)+(4x^2-7x-3)-(3x^2+4x+1)$

$\implies\sf{B+C-A=5x^2-3x+8+4x^2-7x-3-3x^2-4x-1$

$\implies\sf{B+C-A=6x^2-14x+4$

$\boxed{\sf{B+C-A=6x^2-14x+4}}$