Math, asked by mahesh128, 1 year ago

IF A(4,0),B(0,y) and AB=5,find the possible values of y

Answers

Answered by maneesh101
36
I will answer...........
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Answered by erinna
9

The positive value of y is 3.

Step-by-step explanation:

It is given that A(4,0),B(0,y) and AB=5.

We need to find the positive value of y.

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula we get

AB=\sqrt{(0-4)^2+(y-0)^2}

AB=\sqrt{16+y^2}

It is given that AB=5.

\sqrt{16+y^2}=5

Taking square on both sides.

16+y^2=25

y^2=25-16

y^2=9

Taking square root on both sides,

y=\pm \sqrt{9}

y=\pm 3

Therefore, the positive value of y is 3.

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