Question

IF A(4,0),B(0,y) and AB=5,find the possible values of y

Answer 1

I will answer...........

Answer 2

The positive value of y is 3.

Step-by-step explanation:

It is given that A(4,0),B(0,y) and AB=5.

We need to find the positive value of y.

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula we get

$AB=\sqrt{(0-4)^2+(y-0)^2}$

$AB=\sqrt{16+y^2}$

It is given that AB=5.

$\sqrt{16+y^2}=5$

Taking square on both sides.

$16+y^2=25$

$y^2=25-16$

$y^2=9$

Taking square root on both sides,

$y=\pm \sqrt{9}$

$y=\pm 3$

Therefore, the positive value of y is 3.

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