Question

if A(4,0)B(0,y)and AB=5find the possible values of Y

Answer 1

Answer:

The possible value of the y is 3 and -3 .

Step-by-step explanation:

Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As given

if A(4,0) B(0,y)and AB = 5 .

$5= \sqrt{(0-4)^{2}+(y-0)^{2}}$

$5= \sqrt{(4)^{2}+(y)^{2}}$

$5= \sqrt{16+y^{2}}$

Taking square on the both sides of the above equation

$(5)^{2}= (\sqrt{16+y^{2}})^{2}$

$25=16+y^{2}$

$y^{2}=25-16$

$y^{2}=9$

y = √9

$y = \pm 3$

Therefore the possible value of the y is 3 and -3 .