Question

If A(4, 2), B(6, 5) and C(1, 4) be the vertices of triangle ABC and AD is a median,  then find the coordinates of D.​

Answer 1

$\pink{\boxed{\underline{EXPLANATION}}}$

GIVEN THAT:

$➲$ A(4,2), B(6,5), and C(1,4) be the vertices of triangle ABC.

$➲$ AD is a median.

FORMULA:

To find the coordinate of med point of a line whose vertices have been given.

$➡ \: x \: coordinate \: = \frac{x1 + x2}{2} \\ \\ ➡ \: y \: coordinate \: = \frac{y1 + y2}{2}$

SOLUTIONS:

$➲$. AD is the median of triangle ABC, so point D is the med point of side BC .

$➲$ Vertices of B(6,5) and C(1,4)

Now finding the coordinate of D

$&#10145 \: x \: coordinate \: of \: D = \frac{6 + 1}{2} \\ \\ &#10145 \: x \: coordinate \: of \: D = \frac{7}{2} \: \: \: \: \: \: \:$

$&#10145 \: y \: coordinate \: of \: D = \frac{5 + 4}{2} \\ \\ &#10145 \: y \: coordinate \: of \: D = \frac{9}{2} \: \: \: \: \: \: \: \:$