If A = [4/2x-3 x+2/x-1] is a symetrix then x=
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Step-by-step explanation:
4(x-1))-(2x(x+2)-3(x+2)
4x-4-((2x²+4x-3x-6))
4x-4-(2x²+x-6)
4x-4-2x²-x+6=0
-2x²+3x+2=0
2x²-3x-2=0
by factorize
2x²-4x+x-2=0
2x(x-2)+1(x-2)=0
x=2
x=-1/2
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