if a=4/3-√5 find the value of a+4/a
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Answer:
we have,
a= 4/3-√5
so, 1/a = 1/ 4/3-√5
1/a = 1/(4/3-√5)×(4/3+ √5)/ (4/3+√5)
1/a = (4/3 +√5)/ (4/3)²- (√5)²
1/a = (4/3 + √5)/(16/9-5)
1/a =( 4/3+√5)/(-29/5)
1/a = 5(4/3+√5)/-29
1/a = (-5)(4/3+√5)/29
4/a = 4×(-5)(4/3+√5)/29
4/a =( -20)(4/3+√5)/29
Hence, a+4/a = (4/3-√5)+ (-20)(4/3+√5)/29
= 29(4/3-√5)-20(4/3+√5)/ 29
=(116/3- 29√5- 80/3-20√5)/29
=( 36/3-9√5)/29
= (12- 9√5)/29
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