If A(4,3);B(-1,y) and C(3,4) are the vertices of a right angled triangle ABC. Angle A=90°. Then find value of y
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Answer:
Step-by-step explanation:
(AB)²+(AC)²=(BC)²
AB=√( -1-4)²+(y-3)² and AC =√(3-4)²+(4-3)² and BC=√(3--1)²+(4-y)²
(AB)²=(-5)²+y²+9-6y and AC²=(-1)²+(1)² and BC²=(4)²+(4-y)²
AB²=25+9+y²-6y and AC²=1+1 and BC²=16+16+y²-8y
AB²=y²-6y+34 and AC²=2 and BC²=y²-8y+32
AB²+AC²=BC²
y²-6y+34+2=y²-8y+32
y²-y²-6y+8y=32-36
2y= -4
y=(-2)
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