If A(4, 3) B(1 - Y) and C (3, 4) are the vertices of a right angled triangle ABC. angle A=90° .then find the value of Y
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The value of y is equal to 0.
Given in the question that in the triangle ABC the angle A is a right angle. So the side BC which is opposite to angle A is the hypotenuse.
Applying Pythagoras theorem in the triangle ABC -
=> BC² = AB² + AC²
Put the values to get the value of y-
BC = √(4+(4+y)²)
AB = √(9+(3+y)²)
AC = √2
=> 4+(4+y)² = 9+(3+y)² + 2
=> 16 + y² + 8y = y² + 9 + 6y + 7
=> 2y = 0
=> y = 0
The value of y is equal to 0.
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