if A(4,3) B(-1,y) and C(3,4) are the vertices of a right angled triangle ABC, right angled at A, then find the value of y
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slope of AB × slope of AC =-1.
{(y-3)÷(-1-5)}×{(4-3)÷(3-4)}=-1
y-3=-6
y=-3
{(y-3)÷(-1-5)}×{(4-3)÷(3-4)}=-1
y-3=-6
y=-3
KavyasriP:
thank you
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