IF A(4, 3), B(6, -2) and C(a, -3) are the vertices
of a triangle right angled at A, find a
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Answer:
As this is a right angled triangle, using Pythagoras theorem,
AB² + AC² = BC²
With the help of distance formula,
= > ( 4 - 6 )² + ( 3 + 2 )² + ( 4 - a )² + ( 3 + 3 )² = ( 6 - a )² + ( - 2 + 3 )²
= > ( - 2 )² + ( 5 )² + ( 4 - a )² + ( 6 )² = ( 6 - a )² + ( 1) ²
= > 4 + 25 + ( 4 - a )² + 36 = ( 6 - a )² + 1
= > 64 = ( 6 - a )² - ( 4 - a )²
= > 64 = 36 + a² - 12a - 16 - a² + 8a
= > 64 = 20 - 4a
= > a = - 11
Hence the required value of a is - 11
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