Math, asked by munmundutta715, 11 months ago

if a=4.36, b=2.39, c=1.97 then the value of a^3-b^3-c^3_3ab is​

Answers

Answered by athulappuz
1

Answer:

0

Step-by-step explanation:

a^3 - b^3-c^3 - 3abc can also be written as

a^3+(-b^3+(-c^3) - 3abc

when a+b+c =o answer becomes zero

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