Math, asked by debnathprasenji6750, 5 hours ago

If a=4.36, b = 2.39, c = 1.97, then the value of a³-b³-c³-3abc is?

Answers

Answered by SHZ123
1

Answer:

The answer is 0

Hope it helps

Answered by kartiksharma17012007
1

Answer:

a^3 = 82.881856

b^3 = 13.651919

c^3 = 7.645373

3abc = 61.584564

a^3-b^3-c^3-3abc = 82.881856 - 13.651919 - 7.645373 - 61.584564

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