If A (-4 ,8), B (-3, -4) and C (0, -5) and D (5, 6) are the vertices of a quadrilateral ABCD, find its area.
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Let the vertices of the quadrilateral be A(−4, 8), B(−3, −4), C(0, −5) and D(5, 6). Join AC to form two triangles, namely, ΔABC and ΔACD. Thus, the area of quadrilateral ABCD is 72 square units.
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