Question

if A (- 4,8) ;B( - 3, - 4) ;C ( 0 ,- 5) and D(5,6) are the vertices of quadrilateral ABCD, find its area?????​

Answer 1

area[∆ABC] =

1/2 {-4(-4+5)-3(-5-8)+0(8+4)}

= 1/2{-4+39+0)

= 35/2 unit²

area [∆BCD]= 1/2{-3(-5-6)+0(6+4)+5(-4+5)

= 1/2{33+0+5}

= 19 unit ²

area of the quadrilateral= area[∆ABC]+ area [∆BCD]

= 19+17.5

= 36.5 unit²

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