Question

If a=4 & b=5, find the value of a*3 + b*3 – 3a*2b + 3ab*2.

Answer 1

Hey mate thank for the question

Your question is wrong

it is the formula of (a+b)
whole cube

a=4, b=5

=a^3+b^3-3a^2b+3ab^2

putting the value of a and b

=(4)^3+(5)^3-3*(4)^2*5+3*4*(5)^2

=64+125-15*16+12*25

=189-240+300

=489-240

=249

pls mark as brainluest

Answer 2

solution

given that a=4 , b=5

to find 3a+3b-3a*2b+3ab*2

⇒ =3*4+3*5-3*4*2*5+3*4*5*2

⇒=12+15-12*10+12*10

⇒ =12+15-120+120

⇒=27