Question

If a=4, b = 0 and c=-1, find the value of the following:
(i) (a + b + c) (a^2 + b^2 + c^2 - ab-bc-ca)​

Answer 1

Answer:

$(4 + 0 - 1)( {4}^{2} + {0}^{2} + { - 1}^{2} - 4 \times 0 - 0 \times - 1 - ( - 1)4) \\ 3(16 + 1 + 4) \\ 3(21) \\ 63$

Answer 2

Answer:

i) (a+b+c)

4+0+1=5

(a^2+b^3+c^2-ab-bc-ca)

4^2+0^2+(-1)^2-4×0-0×(-1)-(-1)×4

16+0+1-(-0)-(-0)-(-4)

17+0+0+4

17+4

=21