Question

If a=4,b=0,c=-1,find the value of a^3+b^3+c^3-3abc

Answer 1

Answer:

63

Step-by-step explanation:

${a}^{3} + {b}^{3} + {c}^{3} - 3abc \\ = {4}^{3} + {0}^{3} + {( - 1)}^{3} - 3 \times 4 \times 0 \times ( - 1) \\ = 64 + 0 + ( - 1) - 0 \\ = 64 - 1 \\ = 63$

Answer 2

Answer

this eq. will be solved by ; ( a3 + b3 + c3 - 3abc )