Question

if a=4 b=0 c=-1 then what is the value of (a+b+c)(a²+b²+c²-ab-bc-ca)
solve it ​

Answer 1

Answer:

21

Step-by-step explanation:

(a+b+c)+(a²+b²+c²-ab-bc-ca)

=(4+0+1)+(4²+0²+1²-(4×0)-(0×1)-(1×4)

=(5)+(16+1)-(4)-(1)-(4)

=(5)+(17)-(1)

=5+16

21