Question

If a = 4, b=1, c=6 then the value of the square root 4a²2b²c⁴​

Answer 1

Answer:

If a = 4, b=1, c=6 then the value of the square root 4a²2b²c⁴​ is $288\sqrt{2}$.

Step-by-step explanation:

$\sqrt{4a^22b^2c^4}= 2abc^2 \sqrt{2}$

Put the value of a = 4, b = 1 and c= 6, we get

$2abc^2 \sqrt{2} \\ = 2(4) (1) (6)^2 \sqrt{2} \\=8 (36) \sqrt{2}\\= 288\sqrt{2}$

Answer 2

Here we are given an expression 4a²2b²c⁴​

Also, the values of a, b, and c are given

a = 4, b=1, c=6

We have to find the value of the square root of the expression

First, we will find the value of 4a²2b²c⁴​

So, 4a²2b²c⁴​ = 4(4)²2(1)²(6)⁴​

                     = 4 × 16 × 2 × 1 × 1296

                     = 165888

So, √(4a²2b²c⁴) = √(165888)

                          = 407.293

Hence, the value of the square root of 4a²2b²c⁴​ will be 407.293