Question

If a= |=4,|b |=2,|c |=6 and each of the angles between the vectors is 60, t

Answer 1

Step-by-step explanation:

|a|=3,|b|=4,|c|=5

a+b+c=0

a+b =-c

|a+b| =|-c|

|a+b|2 =|-c|2

|a|2 +|b|2 +2a.b =|c|2

9 + 25 +2a.b=49

a.b=3*5

9+25+2ab cos theta=49

15=30cos theta

or cos theta=1/2

theata =60

so angle is 60 degrees

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hope it helps

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