Question

if a=4, b=3, c=2, and d = 0, find the value of : 4ab-cd+2 ​

Answer 1

$\large\sf\underline{Given:-}$

• a = 4

• b = 3

• c = 2

• d = 0

$\large\sf\underline{To\:find:-}$

• Value of 4ab - cd + 2

$\large\sf\underline{Solution :-}$

Substituting the value of a , b , c and d :

$\sf↦\:4ab-cd+2$

$\sf↦\:4 \times 4 \times 3-2 \times 0+2$

$\sf↦\:16\times 3-0+2$

$\sf↦\:48-0+2$

$\tt\purple{↦\:50}$

• Thnku :)

Answer 2

Solution:

Given:

a=4

b=3

c=2

d=0

To find:

4ab-cd+2

Substitute the given values with their respectives.

= 4(4*3)-(2*0)+2

= 4(12)-(2)+2

= 48-2+2 [ note : -2 and +2 are cancelled]

= 48

ANSWER = 48

Hope this answe helps you ʘᴗʘ