if a^4+b^4=a^2+b^2 proove a^6+b^6=0
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Heya! Mate
We are given that
a⁴ + b⁴ = a²b²
What we need to prove is
a⁶ + b⁶ = 0
Here I your proof
a⁶ + b⁶ can be written as (a²)³ + (b²)³
[Since x³ + y³ = (x + y)(x² + y² - xy)]
Therefore
=> (a²)³ + (b²)³ = (a + b)(a⁴ + b⁴ - a²b²)
[given a⁴ + b⁴ = a²b²]
=> (a²)³ + (b²)³ = (a + b)(a²b² - a²b²)
=> a⁶ + b⁶ = (a + b)(0)
=> a⁶ + b⁶ = 0
Thus proved...
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