Question

if a=4,b=5andc=7 then what is the value pf log4 root(a+b+c)?

Answer 1

Answer:

2

Step-by-step explanation:

As you are asking this question i am pretty sure that u r starting out logarithms or your basics are not clear. Assuming that u r just starting out logs here is the solution :-

if

$log_{a} a = 1$

then we bring the subscripted a to the RHS and we can say that a^1 = a

there the value on top of a (power) is the value of the log .

therefore:-

log4 root(a+b+c) = log4 (16)

4^x = 16

hence the value of x = 2.

a quick tip for u "Start logs from NCERT and grasp all the formulas first"

Answer 2

Answer:

Required value is 2.

Step-by-step explanation:

Given,

$a = 4 \\ b = 5 \\ c = 7$

Here we want to find,

$log_{4}(a + b + c)$

We are putting value of a,b and c and get,

$log_{4}(4 + 5 + 7) \\ = log_{4}(16)$

Let,

$x = log_{4}(16) \\ {4}^{x} = 16 \\ {4}^{x} = {4}^{2} \\ x = 2$

So,

$log_{4}(a + b + c) = 2$

Here applied formula,

$if \: log_{x}(y) = a \\then \: y = {x}^{a}$

Some more important Logarithm formulas,

$log_{x}(1) = 0 \\ log_{x}(0) = 1 \\ log_{x}(y) = \frac{ log(x) }{ log(y) } \\ log( {x}^{y} ) = y log(x) \\ log(x) + log(y) = log(xy) \\ log(x) - log(y) = log( \frac{x}{y} ) \\ log_{x}(x) = 1$

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