if a 4-digit number is divided by 2-digit number the remainder is 12 and if double of this number is divided by same divisor remainder is 1 find the 4-digit number and 2-digit number
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Answered by
9
Heya Sarth,
--> Let ur four digit no. be A.. and 2 digit no. be B
--> If B divides A , 12 is remainder => B > 12
--> If B divides 2A , remainder is 1..
So, let's say :->
---> A = mB + 12 <--- when divided by B, the remainder is 12..
=> 2A = mB + 24
=> When, B divides 2A the remainder is 24, but according to the question it is 1
=> B also divides 23 which unfortunately is a prime
=> B = 23....
Now, A = 23m + 12 <-- is what we know about the four and two digit no.s
So, smallest such A is --> 23*43 + 12 = 1001 and largest --> 9994
Hope you get your answer.. :)
--> Let ur four digit no. be A.. and 2 digit no. be B
--> If B divides A , 12 is remainder => B > 12
--> If B divides 2A , remainder is 1..
So, let's say :->
---> A = mB + 12 <--- when divided by B, the remainder is 12..
=> 2A = mB + 24
=> When, B divides 2A the remainder is 24, but according to the question it is 1
=> B also divides 23 which unfortunately is a prime
=> B = 23....
Now, A = 23m + 12 <-- is what we know about the four and two digit no.s
So, smallest such A is --> 23*43 + 12 = 1001 and largest --> 9994
Hope you get your answer.. :)
Answered by
4
Step-by-step explanation:
Divide a 4-Digit Number by a 2-Digit Number
To divide a four-digit number by a two-digit number (for example 3654 � 47), follow these steps:
Place the divisor (47) before the division bracket and place the dividend (3654) under it.
47)3654
Examine the first two digits of the dividend (36). The number 36 is less than 47 so it can't be divided by 47 to produce a whole number. Next take the first three digits of the dividend (365) and determine how many 47's it contains. The number 365 contains seven 47's (7*47=329) but not eight (8*47=376). Place the 7 above the division bracket and directly above the 5.
7
47)3654
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