Question

If A× 4=E ,B÷4=E,C+4=E,D-4=E and A+ B+C+D=100.... then find the value of E​

Answer 1

Answer:

"A, B, C and D with respect to E

So, A*4=E , thus A= E/4

B/4=E, thus B=4E

C+4=E, thus C=E-4

D-4=E, thus the answer for D=E+4

Now, we know that,

A+B+C+D=100

Therefore,

(E/4) + (4E) + (E-4) + (E+4) = 100

=> (E/4) + (4E) + (2E) = 100

=> (E/4) + (6E) =100

=> (25E/4) = 100

=> E= (100*4)/25

=> E=16

The value of E is 16

=> E= (100*4)/25

=> E=16"

Step-by-step explanation:

Hope it helps you

Please mark me as the brainliest

@Follow me for follow back..... ;)

Answer 2

Step-by-step explanation:

__A, B, C and D with respect to E__

So, A*4=E , thus A= E/4

B/4=E, thus B=4E

C+4=E, thus C=E-4

D-4=E, thus the answer for D=E+4

_______Now, we know that,

A+B+C+D=100

Therefore,

(E/4) + (4E) + (E-4) + (E+4) = 100

• (E/4) + (4E) + (2E) = 100

• (E/4) + (6E) =100

• (25E/4) = 100

• E= (100*4)/25
• E=16

•   The value of E is 16

=> E= (100*4)/25

=> [ E=16]

hope it helps u