Question

if a=-4 find the value of x^3-3x+3x^2+6
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Answer 1

Answer:

if x=-4 x^3-3x+3x^2+6=7

Step-by-step explanation:

$x = - 4 \: substitute \: this \: value \: in \: {x}^{3} - 3x + {3x}^{2} + 6 \\ = {(1)}^{3} - 3(1) + 3({1})^{2} + 6 \\ = 1 - 3 + 3(1) + 6 \\ = 1 - 3 + 3 + 6 \\ = - 2 + 9 \\ = 7$

Answer 2

Answer:

78

Step-by-step explanation:

-4³ - 3 × 4 + 3×4² + 6

-64 - 12 + 12² + 6

-72 + 144 + 6

78

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