If A=45 B=30 then prove that sinA/cosA+sinA*sinB=2/3
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Answered by
50
A=45 B=30
sinA/cosA+sinA×sinB
=sin45/cos45+sin45×sin30
1/√2/1/√2+1/√2×1/2
1/√2/1/√2+1/2√2
1/√2/2√2+√2/4
1/√2/3√2/4
1/√2×4/3√2
4/6
2/3
sinA/cosA+sinA×sinB
=sin45/cos45+sin45×sin30
1/√2/1/√2+1/√2×1/2
1/√2/1/√2+1/2√2
1/√2/2√2+√2/4
1/√2/3√2/4
1/√2×4/3√2
4/6
2/3
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4
Answer:
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