Question

If A=45 degree,verify that sin2 A=2sin A * cos A

Answer 1

Answer:

Step-by-step explanation:

sin 2*( 45° ) = 2* sin45°*cos45°

sin 90°= 2*1/√2* 1/√2

1= 2/2

1=1

LHS=RHS

Answer 2

Given, A=45°

Now LHS= sin2A = sin 90° = 1 (it can also be done by using the identity sin2A = 2sinAcosA.)

According to the identity,

Now, RHS= 2sinA. cos A = 2sin 45°. cos45°

= 2× 1/√2 × 1/√2

= 2×1/2

=1

LHS=RHS

HENCE PROVED.

Mark me as the brainliest if I deserve....✌