If a=45 verify that cos2A=2cos^2A-1=1-sin^2A
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a=45°
to prove, cos 2A = 2cos²A - 1 = 1 - sin2A
cos 2A=cos 2×45°
= cos 90°
= 0
2cos²A -1 = 2×(1/√2)² -1
= 2×1/2 - 1
= 1-1 = 0
1- sin2A = 1- (sin 90°)
= 1-1 = 0
that part u know 1- sin²A is wrong.It is 1- sin 2A
If this helps u .......then only mark as brainliest
to prove, cos 2A = 2cos²A - 1 = 1 - sin2A
cos 2A=cos 2×45°
= cos 90°
= 0
2cos²A -1 = 2×(1/√2)² -1
= 2×1/2 - 1
= 1-1 = 0
1- sin2A = 1- (sin 90°)
= 1-1 = 0
that part u know 1- sin²A is wrong.It is 1- sin 2A
If this helps u .......then only mark as brainliest
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