Question

If A = 45° and B = 60°, then tan (A + B)
1 + 3
1+03
(A)
(B)
1
+
1 - 03
(C) 1 + 03
(D) 1 - 03
11.
cos
+x)=
2
(B) - sinx
(D) sinx
(A) cosx (C) -cosx
tan3300 = (A) 03
(C) -3 sin450​

Answer 1

Answer :

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Solution :

Given that :

A = 45° and B = 60°

tan(A+B) = (tanA + tanB) / 1 - tanA. tanB

=> (tan45°+tan60°)/1-tan45°.tan60°

=> (1+√3)/(1-1×√3)

=> (1+√3)/(1-√3)

$= > \frac{1 + \sqrt{3} }{ 1- \sqrt{3} } \times \frac{1 + \sqrt{3} }{1 + \sqrt{3} } = \frac{1 + 2 \sqrt{3} + 3 }{1 - 3} \\ \\ = > \frac{4 + 2 \sqrt{3} }{ - 2} = - ( 2 + \sqrt{3} )$

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I hope it will help you ☺

Fóllòw Më ❤