Math, asked by bhavya83883, 3 days ago

If A = 4a2+ b2– 6ab B = 3b2+ 12a2+ 8ab C = 6a2+ 8b2+ 6ab Find (i) A + B + C (ii) (A – B) –C with solution

Answers

Answered by sunidhibhakuni28

1

Answer:

22a^2 + 12b^2 + 8ab
-14a^2 - 10b^2 - 20ab

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