Question

If a=4lm/(l+m), find value of
(a+2l)/(a-2l)+ (a+2m)/(a-2m)

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The value of (a+2l)/(a-2l)+ (a+2m)/(a-2m) is 2.

• Given that, a = $\frac{4ml}{l+m}$.
• we have to find the value of (a+2l)/(a-2l)+ (a+2m)/(a-2m)

We solve the expression further,

$\frac{a+2l}{a-2l}$ + $\frac{a+2m}{a-2m}$

• Cross multiplying , we get

= $\frac{(a+2l)(a-2m)}{(a-2l)(a-2m)}$ + $\frac{(a+2m)(a-2l)}{(a-2l)(a-2m)}$

= $\frac{(a+2l)(a-2m) + (a+2m)(a-2l)}{(a-2l)(a-2m)}$

= $\frac{(a^2-2am+2al-4ml) + (a^2+2am-2al-4ml)}{(a^2-2am-2al+4ml)}$

= $\frac{(2a^2-8ml)}{(a^2-2a(m+l)+4ml)}$

• Using the given,

2a(l+m) = 8ml  

• Substituting the value of 2a(l+m) = 8ml in the denominator.

= $\frac{(2a^2-8ml)}{(a^2-8ml+4ml)}$

= $\frac{2(a^2-4ml)}{(a^2-4ml)}$

= 2