Question

If a=4lm/l+m,then the value of a+2l/a-2l+a+2m/a-2m

Answer 1

It would be 2.

Step-by-step explanation:

Given expression,

$\frac{a+2l}{a-2l}+\frac{a+2m}{a-2m}$

$=\frac{(a+2l)(a-2m)+(a+2m)(a-2l)}{(a-2l)(a-2m)}$

$=\frac{a^2 - 2am + 2al - 4lm+a^2 - 2al + 2ma - 4lm}{a^2 - 2ma - 2al + 4lm}$

$=\frac{2a^2 -8lm}{a^2 - 2ma - 2al + 4lm}$   ....(1)

Now, we have,

$a=\frac{4lm}{l+m}$

$\implies a(l+m) = 4lm$

$\implies 2a(l+m) = 8lm$

From equation (1),

$\frac{2a^2 -2a(l+m)}{a^2 - 2ma - 2al + a(l+m)}$

$=\frac{2a^2 - 2a(l+m)}{a^2 - 2a(l+m) + a(l+m)}$

$=\frac{2a^2 - 2a(l+m)}{a^2 - a(l+m)}$

$=\frac{2(a^2 - a(l+m))}{a^2 - a(l+m)}$

= 2

#Learn more:

How to add fractions :

https://brainly.in/question/68691

Answer 2

Step-by-step explanation:

aagay khud kro friend

bye bye