If a = 4q+r, and r= 1 then possible value "a" of the following.
A) 6
B) 8
D) 11
C) 9
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a=4q+r
r=1
a=4q+1
when q=1
a=4 x 1 +1
a= 5
when q=2
a= 4 x 2 +1
a= 9
when q = 3
a= 4 x 3 +1
a=12
Here we are exceeding the options
so we have an answer
when q= 2
a will probably have a value of 9
So Possible value of a can be 9
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